Arthur, Iowa | |
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City | |
Location of Arthur, Iowa |
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Coordinates: 42°20′7″N 95°20′48″W / 42.33528°N 95.34667°WCoordinates: 42°20′7″N 95°20′48″W / 42.33528°N 95.34667°W | |
Country | United States |
State | Iowa |
County | Ida |
Area | |
• Total | 0.15 sq mi (0.39 km2) |
• Land | 0.15 sq mi (0.39 km2) |
• Water | 0 sq mi (0 km2) |
Elevation | 1,293 ft (394 m) |
Population (2010) | |
• Total | 206 |
• Estimate (2016) | 203 |
• Density | 1,373/sq mi (530.2/km2) |
Time zone | Central (CST) (UTC-6) |
• Summer (DST) | CDT (UTC-5) |
ZIP code | 51431 |
Area code(s) | 712 |
FIPS code | 19-03115 |
GNIS feature ID | 0454245 |
Arthur is a city in Ida County, Iowa, United States. The population was 206 at the 2010 census.
Arthur was platted in 1885. It was named for Chester A. Arthur, 21st President of the United States.
Arthur is located at 42°20′7″N 95°20′48″W / 42.33528°N 95.34667°W (42.335225, -95.346658).
According to the United States Census Bureau, the city has a total area of 0.15 square miles (0.39 km2), all of it land.
As of the census of 2010, there were 206 people, 95 households, and 60 families residing in the city. The population density was 1,373.3 inhabitants per square mile (530.2/km2). There were 113 housing units at an average density of 753.3 per square mile (290.9/km2). The racial makeup of the city was 98.1% White, 0.5% African American, and 1.5% from other races. Hispanic or Latino of any race were 1.5% of the population.
There were 95 households of which 24.2% had children under the age of 18 living with them, 48.4% were married couples living together, 7.4% had a female householder with no husband present, 7.4% had a male householder with no wife present, and 36.8% were non-families. 31.6% of all households were made up of individuals and 21% had someone living alone who was 65 years of age or older. The average household size was 2.17 and the average family size was 2.68.