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1938 U.S. National Championships – Women's Singles

Women's Singles
1938 U.S. National Championships
Champion United States Alice Marble
Runner-up Australia Nancye Wynne
Final score 6–0, 6–3
Details
Draw 64
Seeds 16
Events
Singles men women
Doubles men women
← 1937 · U.S. National Championships · 1939 →

Second-seeded Alice Marble defeated Nancye Wynne 6–0, 6–3 in the final to win the Women's Singles tennis title at the 1938 U.S. National Championships.

The tournament used two lists of eight players for seeding the women's singles event; one for U.S. players and one for foreign players. Alice Marble is the champion; others show in brackets the round in which they were eliminated.


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Wikipedia

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