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New York City mayoral election, 1993

New York City mayoral election, 1993
New York City
← 1989 November 3, 1993 1997 →
  Rudy Giuliani.jpg David dinkins.jpg
Candidate Rudy Giuliani David Dinkins
Party Republican Democratic
Alliance Liberal -
Popular vote 930,236 876,869
Percentage 50.9% 48.0%

NYC Mayoral Election 1993 Results by Borough.svg
Results by Borough
  Dinkins—60-70%
  Dinkins—50-60%
  Giuliani—60-70%
  Giuliani—80-90%

Mayor before election

David Dinkins
Democratic

Elected Mayor

Rudy Giuliani
Republican


David Dinkins
Democratic

Rudy Giuliani
Republican

The New York City mayoral election of 1993 occurred on Tuesday, November 2, 1993, with Republican nominee U.S. Attorney for the Southern District of New York Rudolph Giuliani narrowly defeating incumbent Democratic mayor David Dinkins. They also faced several third-party candidates.

The election was a re-match between the same two candidates from 1989, when Dinkins had narrowly defeated Giuliani to win the mayoralty.

Dinkins had narrowly defeated Giuliani in the previous election. As in his unsuccessful 1989 campaign, Giuliani also ran on the Liberal Party ballot, while the Conservative Party line was held by activist George Marlin. The city was suffering from a spike in unemployment associated with a nationwide recession, and with a rise in local unemployment rates from 6.7% in 1989 to 11.1% in 1992. Giuliani promised to focus the police department on shutting down petty crimes and nuisances as a way of restoring the quality of life:

It's the street tax paid to drunks and panhandlers. It's the squeegee men shaking down the motorist waiting at a light. It's the trash storms, the swirling mass of garbage left by peddlers and panhandlers, and open-air drug bazaars on unclean streets.

Although crime had begun to fall during the Dinkins administration, the city's crime rate was a key issue in the 1993 election, with Dinkins suffering badly from a perception that crime was uncontrolled in the city.


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