Lake Arthur, Louisiana
| Town of Lake Arthur | |
| Town | |
| Country | United States |
|---|---|
| State | Louisiana |
| Parish | Jefferson Davis |
| Elevation | 7 ft (2.1 m) |
| Coordinates | 30°7′0″N 92°40′37″W / 30.11667°N 92.67694°WCoordinates: 30°7′0″N 92°40′37″W / 30.11667°N 92.67694°W |
| Area | 2.4 sq mi (6.2 km2) |
| - land | 1.9 sq mi (5 km2) |
| - water | 0.6 sq mi (2 km2), 25% |
| Population | 3,007 (2000) |
| Density | 1,621.0/sq mi (625.9/km2) |
| Timezone | CST (UTC-6) |
| - summer (DST) | CDT (UTC-5) |
| Area code | 337 |
  Location of Lake Arthur in Louisiana
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 Location of Louisiana in the United States
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Lake Arthur is a town in Jefferson Davis Parish, Louisiana, United States. The population was 3,007 at the 2000 census. It is part of the Jennings Micropolitan Statistical Area. The current mayor is Robbie Bertrand.
According to the United States Census Bureau, the town has a total area of 2.4 square miles (6.2 km2), of which, 1.9 square miles (4.9 km2) of it is land and 0.6 square miles (1.6 km2) of it (23.46%) is water.
As of the census of 2000, there were 3,007 people, 1,192 households, and 803 families residing in the town. The population density was 1,621.0 people per square mile (627.6/km²). There were 1,365 housing units at an average density of 735.8 per square mile (284.9/km²). The racial makeup of the town was 88.19% White, 10.87% African American, 0.07% Native American, 0.10% Asian, 0.03% Pacific Islander, and 0.73% from two or more races. Hispanic or Latino of any race were 0.73% of the population.
There were 1,192 households out of which 32.5% had children under the age of 18 living with them, 48.0% were married couples living together, 15.5% had a female householder with no husband present, and 32.6% were non-families. 28.2% of all households were made up of individuals and 12.9% had someone living alone who was 65 years of age or older. The average household size was 2.52 and the average family size was 3.11.
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