Greasewood, Arizona | |
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CDP | |
Location in Navajo County and the state of Arizona |
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Location in the United States | |
Coordinates: 35°31′32″N 109°51′54″W / 35.52556°N 109.86500°WCoordinates: 35°31′32″N 109°51′54″W / 35.52556°N 109.86500°W | |
Country | United States |
State | Arizona |
County | Navajo |
Area | |
• Total | 5.3 sq mi (13.7 km2) |
• Land | 5.3 sq mi (13.8 km2) |
• Water | 0.0 sq mi (0.0 km2) |
Elevation | 5,910 ft (1,801 m) |
Population (2000) | |
• Total | 581 |
• Density | 108.7/sq mi (42.0/km2) |
Time zone | MST (UTC-7) |
FIPS code | 04-29430 |
GNIS feature ID | 0005336 |
Greasewood (Navajo: Díwózhii Biiʼ Tó) is a census-designated place (CDP) in Navajo County, Arizona, United States. The population was 581 at the 2000 census.
Greasewood is located at 35°31′32″N 109°51′54″W / 35.52556°N 109.86500°W (35.525467, -109.865005).
According to the United States Census Bureau, the CDP has a total area of 5.3 square miles (14 km2), all of it land.
As of the census of 2000, there were 581 people, 126 households, and 106 families residing in the CDP. The population density was 108.7 people per square mile (42.0/km²). There were 182 housing units at an average density of 34.1/sq mi (13.2/km²). The racial makeup of the CDP was 2.41% White, 97.07% Native American, 0.17% Pacific Islander, 0.17% from other races, and 0.17% from two or more races. 0.69% of the population were Hispanic or Latino of any race.