Desert Hills, Arizona | |
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CDP | |
Location in Mohave County and the state of Arizona |
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Location in the United States | |
Coordinates: 34°32′51″N 114°22′0″W / 34.54750°N 114.36667°WCoordinates: 34°32′51″N 114°22′0″W / 34.54750°N 114.36667°W | |
Country | United States |
State | Arizona |
County | Mohave |
Area | |
• Total | 4.7 sq mi (12.2 km2) |
• Land | 4.7 sq mi (12.2 km2) |
• Water | 0.0 sq mi (0.0 km2) |
Elevation | 542 ft (165 m) |
Population (2000) | |
• Total | 2,183 |
• Density | 463.8/sq mi (179.1/km2) |
Time zone | MST (UTC-7) |
FIPS code | 04-18740 |
GNIS feature ID | 1866982 |
Desert Hills is a census-designated place (CDP) in Mohave County, Arizona, United States. The population was 2,183 at the 2000 census.
Desert Hills is located at 34°32′51″N 114°22′0″W / 34.54750°N 114.36667°W (34.547363, -114.366781).
According to the United States Census Bureau, the CDP has a total area of 4.7 square miles (12 km2), all of it land.
As of the census of 2000, there were 2,183 people, 997 households, and 677 families residing in the CDP. The population density was 463.8 people per square mile (179.0/km²). There were 1,463 housing units at an average density of 310.8/sq mi (119.9/km²). The racial makeup of the CDP was 93.08% White, 0.14% Black or African American, 0.55% Native American, 0.37% Asian, 4.44% from other races, and 1.42% from two or more races. 9.30% of the population were Hispanic or Latino of any race.