As the positive integer n{\displaystyle n} becomes larger and larger, the value n⋅sin(1n){\displaystyle n\cdot \sin {\bigg (}{\frac {1}{n}}{\bigg )}} becomes arbitrarily close to 1{\displaystyle 1}. We say that "the limit of the sequence n⋅sin(1n){\displaystyle n\cdot \sin {\bigg (}{\frac {1}{n}}{\bigg )}} equals 1{\displaystyle 1}."
