Anastasiya Yakimova
Yakimova at the 2011 US Open
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| Country (sports) |
 Belarus
|
|---|---|
| Residence | Las Palmas de Gran Canaria, Spain |
| Born |
1 November 1986 Minsk, Soviet Union |
| Height | 1.65 m (5 ft 5 in) |
| Turned pro | 2001 |
| Plays | Right-handed (two-handed backhand) |
| Prize money | $1,071,318 |
| Singles | |
| Career record | 339-233 |
| Career titles | 0 WTA, 12 ITF |
| Highest ranking | No. 49 (31 July 2006) |
| Grand Slam Singles results | |
| Australian Open | 3R (2007) |
| French Open | 2R (2006, 2008) |
| Wimbledon | 2R (2011, 2012) |
| US Open | 2R (2011) |
| Doubles | |
| Career record | 122–100 |
| Career titles | 2 WTA, 10 ITF |
| Highest ranking | No. 67 (19 June 2006) |
| Team competitions | |
| Fed Cup | 10–13 |
| Last updated on: 26 June 2014. | |
Anastasiya Yakimova (Belarusian: Настасся Аляксееўна Якімава; Анастасия Алексеевна Екимова; born 1 November 1986) is a tennis player from Belarus. She made it to the third round of the 2007 Australian Open, defeating Ai Sugiyama of Japan, a seeded player, on the way in the second round.
Yakimova began the year by qualifying for the Medibank International. She defeated Stéphanie Cohen-Aloro, Sophie Ferguson and Klára Zakopalová en route to qualifying. She faced Annabel Medina Garrigues in the first round and lost in three sets. She then headed to the Australian Open where she lost to Gisela Dulko, also in three sets. She then played her first ITF tournament of the year at the $50,000 Cali event in Colombia. As the fourth seed Yakimova battled through to the final where she defeated Rossana de los Ríos to take her seventh ITF title.
She then qualified for both Indian Wells and Miami, two premier mandatory events. In Indian Wells she defeated American Varvara Lepchenko before falling to reigning champion Ana Ivanovic. In Miami she defeated fellow Belarusian Olga Govortsova and then 13th seed Marion Bartoli to reach the third round. Here she lost to Alisa Kleybanova.
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