Aliaksandra Sasnovich
Sasnovich at the 2015 Wimbledon Championships
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| Full name | Aliaksandra Alexandrovna Sasnovich |
|---|---|
| Country (sports) |
 Belarus
|
| Born |
22 March 1994 Minsk, Belarus |
| Height | 1.74 m (5 ft 9 in) |
| Prize money | $604,317 |
| Singles | |
| Career record | 186–102 |
| Career titles | 11 ITF |
| Highest ranking | 92 (6 October 2014) |
| Current ranking | 104 (11 July 2016) |
| Grand Slam Singles results | |
| Australian Open | 2R (2016) |
| French Open | 1R (2016) |
| Wimbledon | 2R (2015, 2016) |
| US Open | 2R (2014) |
| Doubles | |
| Career record | 68–44 |
| Career titles | 7 ITF |
| Highest ranking | 142 (28 October 2013) |
| Current ranking | — |
| Grand Slam Doubles results | |
| Wimbledon | Q1 (2016) |
| Team competitions | |
| Fed Cup | 14–9 |
| Last updated on: 11 July 2016. | |
Aliaksandra Aliaksandrawna Sasnovich (Belarusian: Аляксандра Аляксандраўна Сасновіч; born 22 March 1994 in Minsk) is a Belarusian tennis player.
Sasnovich has won eleven singles and seven doubles titles on the ITF tour in her career. On 6 October 2014, she reached her best singles ranking of world number 92. On 28 October 2013, she peaked at world number 142 in the doubles rankings.
Playing for Belarus at the Fed Cup, Sasnovich has a win–loss record of 14–9.
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