1967 NFL playoffs
| Dates | December 23–31, 1967 | ||||
|---|---|---|---|---|---|
| Teams | 4 | ||||
| Champions | Green Bay Packers | ||||
| Runners-up | Dallas Cowboys | ||||
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The NFL playoffs following the 1967 NFL season culminated in the NFL championship game on New Year's Eve, and determined who would represent the league against the American Football League champions in Super Bowl II.
With 16 teams in the league in 1967, this was the first season that the NFL used a four-team playoff tournament. The four division winners advanced to the postseason, with the two division winners in each conference meeting in the first round (effectively being conference championship games). The championship game this year was the famous Ice Bowl, played in Green Bay on December 31.
Although the Baltimore Colts (11–1–2) had tied for the best record in the league, they lost the new division tie-breaker to the Los Angeles Rams and were excluded from the postseason.
Within each conference, the two division winners qualified for the playoffs. In the first round, the Capitol Division winner met the Century Division winner in the Eastern Conference game, while the Coastal Division winner faced the Central Division winner in the Western Conference game. The conference champions advanced to the NFL Championship Game, whose winner played the American Football League champion in the Super Bowl. The losers of the conference championship games met in the third place Playoff Bowl at the Orange Bowl in Miami, Florida.
Prior to 1975, the playoff sites rotated and were known prior to the start of the season. In 1967, the hosts were the Capitol and Central division winners for the conference championships (first round), and the Western Conference for the championship game, effectively giving home field advantage to the Central Division winner, the two-time defending NFL champion Green Bay Packers. The 1968 playoff hosts were Century, Coastal, and Eastern, respectively, and 1969 was like 1967.
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