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1948 U.S. National Championships – Women's Singles

Women's Singles
1948 U.S. National Championships
Champion United States Margaret Osborne duPont
Runner-up United States Louise Brough
Final score 4–6, 6–4, 15–13
Events
Singles men women
Doubles men women
← 1947 · U.S. National Championships · 1949 →

Third-seeded Margaret Osborne duPont defeated Louise Brough 4–6, 6–4, 15–13 in the final to win the Women's Singles tennis title at the 1948 U.S. National Championships.

The seven seeded U.S. players are listed below. Margaret Osborne duPont is the champion; others show in brackets the round in which they were eliminated.


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Wikipedia

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