1948 NBA Playoffs
| 1948 BAA playoffs | |||||
|---|---|---|---|---|---|
| Season | 1947–48 | ||||
| Teams | 6 | ||||
| Champions | Baltimore Bullets (1st title) | ||||
| Runner-up | Philadelphia Warriors (2nd finals appearance) | ||||
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The 1948 BAA Playoffs was the postseason tournament following the Basketball Association of America 1947–48 season. (Following its third, 1948–49 season, the BAA and National Basketball League merged to create the National Basketball Association or NBA.) The tournament concluded with the Baltimore Bullets defeating the Philadelphia Warriors 4 games to 2 in the BAA Finals.
The two Division champions and two teams involved in a 3-way tiebreaker began tournament play on Tuesday, March 23, and the Finals concluded on Wednesday, April 21. Baltimore and Philadelphia played 12 and 13 games in the span of 30 days; their six final games in 12 days.
There were no byes. Western and Eastern champions St. Louis and Philadelphia immediately played a long semifinal series with St. Louis having home-court advantage. Philadelphia won the seventh game in St. Louis, 85–46, two days before Baltimore concluded its sequence of tie-breaker (not shown) and two short series with other runners-up.
Chicago Stags vs. Washington Capitols: Stags win series 1-0
Chicago Stags vs. Baltimore Bullets: Bullets win series 1-0
(W2) Baltimore Bullets vs. (E2) New York Knicks: Bullets win series 2-1
This was the first playoff series between the Bullets and Knicks.
(E3) Boston Celtics vs. (W3) Chicago Stags: Stags win series 2-1
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