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1925 Giro d'Italia

Route of the 13th Giro d'Italia.
Route of the 13th Giro d'Italia.
Race details
Dates 16 May – 7 June
Stages 12
Distance 3,520.5 km (2,188 mi)
Winning time 137h 31' 13"
Results
  Winner  Alfredo Binda (ITA) (Legnano)
  Second  Costante Girardengo (ITA) (Wolsit-Pirelli)
  Third  Giovanni Brunero (ITA) (Legnano)

  Team Legnano
← 1924
1926 →
  Winner  Alfredo Binda (ITA) (Legnano)
  Second  Costante Girardengo (ITA) (Wolsit-Pirelli)
  Third  Giovanni Brunero (ITA) (Legnano)

  Team Legnano

The 1925 Giro d'Italia was the 13th edition of the Giro d'Italia, a cycling race organized and sponsored by the newspaper La Gazzetta dello Sport. The race began on 16 May in Milan with a stage that stretched 278.1 km (173 mi) to Turin, finishing back in Milan on 7 June after a 307.9 km (191 mi) stage and a total distance covered of 3,520.5 km (2,188 mi). The race was won by the Alfredo Binda of the Legnano team. Second and third respectively were the Italian riders Costante Girardengo and Giovanni Brunero.

Of the 126 riders that began the Giro d'Italia on 16 May, 39 of them made it to the finish in Milan on 7 June. Riders were allowed to ride on their own or as a member of a team. There were six teams that competed in the race: Aliprandi-Pirelli, Jenis, Legnano-Pirelli, Olympia-Pirelli, Peugeot-Pirelli, and Wolsit-Pirelli.

The peloton was completely composed of Italians. The field featured two former Giro d'Italia champions in the 1919 Giro d'Italia winner Costante Girardengo and returning champion Giovanni Brunero. Other notable Italian riders that started the race included Gaetano Belloni, Giovanni Rossignoli, and Pietro Bestetti. This was the first Giro d'Italia that Alfredo Binda competed in.

There were 39 cyclists who had completed all twelve stages. For these cyclists, the times they had needed in each stage was added up for the general classification. The cyclist with the least accumulated time was the winner.


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